# How do you multiply (t-3)(t^2+3t+9)?

Apr 27, 2017

$= {t}^{3} - 27$

#### Explanation:

${a}^{3} - {b}^{3} = \left(a - b\right) \left({a}^{2} + a b + {b}^{2}\right)$

Similarly

$\left(t - 3\right) \left({t}^{2} + 3 t + 9\right)$ can be written as

${t}^{3} - {3}^{3}$

$= {t}^{3} - 27$