How do you multiply #(x+2)^3#?
1 Answer
Mar 18, 2016
Explanation:
Split the function into 'parts' as follows.
# (x + 2)^3 = (x + 2)(x+ 2 )^2# now expand
#(x + 2)^2" using FOIL or any method you use " #
# (x + 2 )^2 = x^2 + 2x + 2x + 4 = x^2 + 4x + 4 # we now have :
# (x + 2)(x^2 + 4x + 4) # multiply each term in 2nd bracket by x , then +2
hence :
#x^3 + 4x^2 + 4x + 2x^2 + 8x + 8 # finally collect like terms :
# x^3 + 6x^2 + 12x + 8 #
