How do you multiply #(x+2)^3#?

1 Answer
Mar 18, 2016

Answer:

# x^3 + 6x^2 + 12x + 8 #

Explanation:

Split the function into 'parts' as follows.

# (x + 2)^3 = (x + 2)(x+ 2 )^2#

now expand #(x + 2)^2" using FOIL or any method you use " #

# (x + 2 )^2 = x^2 + 2x + 2x + 4 = x^2 + 4x + 4 #

we now have : # (x + 2)(x^2 + 4x + 4) #

multiply each term in 2nd bracket by x , then +2

hence : #x^3 + 4x^2 + 4x + 2x^2 + 8x + 8 #

finally collect like terms : # x^3 + 6x^2 + 12x + 8 #