How do you multiply #(x + 3)^2#?

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Answer 1 · 2017-01-15T10:33:43

#=x^2 +6x +9#

Note that the square means the base multiplied by itself..

#7^2 = 7xx7 = 49#

#x^2 = x xx x#

#(x+3)^2 = (x+3)(x+3)#

Each term in the first bracket is to be multiplied by each term in the second bracket.

#(color(blue)(x)color(red)(+3))(x+3)#

#=color(blue)(x)(x+3)color(red)(+3)(x+3)#

#=color(blue)(x^2+3x) color(red)(+3x+9)" "larr# there are 4 terms

#=x^2 +6x +9#

DO not make the mistake of just squaring each to the terms.

#(x+3)^2 != x^2 +9#