How do you multiply #(x^5-1)(x^2+2)#?

1 Answer

Answer:

#x^10+2x^5-x^2-2#

Explanation:

Use FOIL. First multiply the first terms in either binomial to get #x^10#, then multiply the first term in the first binomial with the second term in the second binomial to get #2x^5#, then multiply the second term in the first binomial with the first term in the second binomial to get #-x^2#, then finally multiply the second terms in either binomial to get #-2#.

Put them all together for

#x^10+2x^5-x^2-2#