How do you multiply #(x+8)(x^2-7x-3)#?

1 Answer
May 9, 2015

#(x+8)(x^2−7x−3)#

There are several ways to do this.
One method is to separate the two terms of the first factor and multiply the second factor by each separately before recombining:

#(color(red)(x)+color(blue)(8))(x^2−7x−3)#

#=color(red)(x(x^2-7x-3)) + color(blue)(8(x^2-7x-3))#

#= color(red)(x^3-7x^2-3x) + color(blue)(8x^2-56x-24)#

#= x^3 +x^2-59x-24#