Question

How do you name the slope and y-intercept of `4x-8y=16`?

Answer 1

The slope for the equation in this problem is `1/2` and the y-intercept is `-2`

Explanation:

To solve this problem first put the equation into standard form by solving for `y`:

`4x - 8y + 8y - 16 = 16 - 16 + 8y`

`4x - 0 - 16 = 0 + 8y`

`4x - 16 = 8y`

`(4x - 16)/8 = (8y)/8`

`(4x)/8 - 16/8 = (cancel(8)y)/cancel(8)`

`1/2x - 2 = y` or `y = 1/2x - 2`

The standard form is also:

`color(red)(y = mx - y_1)` where `m` is the slope and `y_1` is the y-intercept.

Therefore the slope for the equation in this problem is `1/2` and the y-intercept is `-2`