How do you name the slope and y-intercept of #4x-8y=16#?

1 Answer
Dec 13, 2016

Answer:

The slope for the equation in this problem is #1/2# and the y-intercept is #-2#

Explanation:

To solve this problem first put the equation into standard form by solving for #y#:

#4x - 8y + 8y - 16 = 16 - 16 + 8y#

#4x - 0 - 16 = 0 + 8y#

#4x - 16 = 8y#

#(4x - 16)/8 = (8y)/8#

#(4x)/8 - 16/8 = (cancel(8)y)/cancel(8)#

#1/2x - 2 = y# or #y = 1/2x - 2#

The standard form is also:

#color(red)(y = mx - y_1)# where #m# is the slope and #y_1# is the y-intercept.

Therefore the slope for the equation in this problem is #1/2# and the y-intercept is #-2#