# How do you name the slope and y-intercept of 4x-8y=16?

Dec 13, 2016

The slope for the equation in this problem is $\frac{1}{2}$ and the y-intercept is $- 2$

#### Explanation:

To solve this problem first put the equation into standard form by solving for $y$:

$4 x - 8 y + 8 y - 16 = 16 - 16 + 8 y$

$4 x - 0 - 16 = 0 + 8 y$

$4 x - 16 = 8 y$

$\frac{4 x - 16}{8} = \frac{8 y}{8}$

$\frac{4 x}{8} - \frac{16}{8} = \frac{\cancel{8} y}{\cancel{8}}$

$\frac{1}{2} x - 2 = y$ or $y = \frac{1}{2} x - 2$

The standard form is also:

$\textcolor{red}{y = m x - {y}_{1}}$ where $m$ is the slope and ${y}_{1}$ is the y-intercept.

Therefore the slope for the equation in this problem is $\frac{1}{2}$ and the y-intercept is $- 2$