How do you normalize #<0, 4, 4>#?

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Answer 1 · 2017-03-26T13:53:58

The normalized vector is

#v/|v|#

where #|v|=sqrt(u_x^2+u_y^2+u_z^2)#

hence #|v|=sqrt(0^2+4^2+4^2)# or #|v|=4*sqrt2#

Hence

#v/|v|=(0/(4*sqrt2) , 4/[4*sqrt2],4/[4*sqrt2])#

#v/|v|=(0,1/sqrt2,1/sqrt2)#