# How do you order the following from least to greatest -sqrt49, -sqrt7, 0, -sqrt51, -6.8?

Apr 21, 2017

$\text{-"sqrt51, "-"sqrt49, "-"6.8, "-} \sqrt{7} , 0$

#### Explanation:

If $x > y$ then $\sqrt{x} > \sqrt{y}$. If $x > y$ then $\text{-"x<"-} y$.

We know that $0$ is the greatest because everything else is negative, thus less than zero. We also know that $\text{-"sqrt51<"-"sqrt49<"-} \sqrt{7}$ because of the rules above.

Finally, since $\text{-"sqrt9<"-"sqrt7<"-} \sqrt{4}$ because of the rules above, $\text{-} \sqrt{7}$ is between $\text{-} 3$ and $\text{-} 2$, so $\text{-"sqrt7<"-"6.8<"-} \sqrt{49}$ because $\text{-"sqrt49="-} 7$.

Thus, $\text{-"sqrt51<"-"sqrt49<"-"6.8<"-} \sqrt{7} < 0$