How do you order the following from least to greatest #-sqrt49, -sqrt7, 0, -sqrt51, -6.8#?

1 Answer
Apr 21, 2017

Answer:

#"-"sqrt51, "-"sqrt49, "-"6.8, "-"sqrt7, 0#

Explanation:

If #x>y# then #sqrtx>sqrty#. If #x>y# then #"-"x<"-"y#.

We know that #0# is the greatest because everything else is negative, thus less than zero. We also know that #"-"sqrt51<"-"sqrt49<"-"sqrt7# because of the rules above.

Finally, since #"-"sqrt9<"-"sqrt7<"-"sqrt4# because of the rules above, #"-"sqrt7# is between #"-"3# and #"-"2#, so #"-"sqrt7<"-"6.8<"-"sqrt49# because #"-"sqrt49="-"7#.

Thus, #"-"sqrt51<"-"sqrt49<"-"6.8<"-"sqrt7<0#