How do you order the following from least to greatest #-sqrt5, pi/2, pi/3, 4 5/8, sqrt18#?

1 Answer
Mar 28, 2017

Answer:

#-sqrt(5), pi/3, pi/2, sqrt(18), 4 5/8#

Explanation:

#-sqrt(5)# is the only negative number so it is the smallest.

#1/3 < 1/2#, so #pi = 3.14159...# will make #pi/3 ~~ 1# and #pi/2 ~~ 1.5#

#sqrt(18)# is close to #sqrt(16) = 4#, so #sqrt(18) ~~ 4.2#

#5/8 = 0.625#, so #4 5/8 = 4.625#