How do you order the following from least to greatest #-sqrt5, pi/2, pi/3, 4 5/8, sqrt18#? Algebra Properties of Real Numbers Order of Real Numbers 1 Answer marfre Mar 28, 2017 Answer: #-sqrt(5), pi/3, pi/2, sqrt(18), 4 5/8# Explanation: #-sqrt(5)# is the only negative number so it is the smallest. #1/3 < 1/2#, so #pi = 3.14159...# will make #pi/3 ~~ 1# and #pi/2 ~~ 1.5# #sqrt(18)# is close to #sqrt(16) = 4#, so #sqrt(18) ~~ 4.2# #5/8 = 0.625#, so #4 5/8 = 4.625# Related questions What are Real Numbers? What does it mean to order a set of real numbers? What are the different types of rational numbers? What kind of rational number is 0? How do you classify real numbers? How do you compare real numbers? What are examples of non real numbers? How would you categorize the number #\frac{\sqrt{36}}{9}#? Which number is larger between #\frac{\pi}{15}# and #\frac{\sqrt{3}}{\sqrt{75}}#? How would you classify each of the following numbers: #\frac{\sqrt{12}}{2}, 1.5\cdot \sqrt{3}, ... See all questions in Order of Real Numbers Impact of this question 647 views around the world You can reuse this answer Creative Commons License