# How do you order the following from least to greatest -sqrt8, -3.1, sqrt15, (-2)^2, -sqrt11?

Mar 28, 2017

These numbers from least to greatest are

$\left\{- \sqrt{11} , - 3.1 , - \sqrt{8} , \sqrt{15} , {\left(- 2\right)}^{2}\right\}$

#### Explanation:

The best way to compare is to convert each number into decimal form, up to certain places of decimal say $4$ and then compare them

$- \sqrt{8} = - 2 \sqrt{2} = - 2 \times 1.4142 = - 2.8284$

$- 3.1 = - 3.1000$

$\sqrt{15} = 3.8730$

${\left(- 2\right)}^{2} = 4.0000$

$- \sqrt{11} = - 3.3166$

Hence, these numbers from least to greatest are

$\left\{- \sqrt{11} , - 3.1 , - \sqrt{8} , \sqrt{15} , {\left(- 2\right)}^{2}\right\}$