Question

How do you perform the operation and write the result in standard form given `(6-2i)(2-3i)`?

Answer 1

`6-22i`

Explanation:

The standard form is `color(blue)a+color(red)bi`

`(6-2i)(2-3i)=12-18i-4i+6i^2`

Add like terms

`=12-22i+6i^2`

Apply the definition `i^2=-1`

`=12-22i+6(-1)`
`=12-22i-6`
`=color(blue)(6)color(red)-color(red)22i`