# How do you plot the polar coordinate (2, (11pi)/6)?

The given polar coordinates $\left(r , \setminus \theta\right) \setminus \equiv \left(2 , \frac{11 \setminus \pi}{6}\right)$ has the following Cartesian coordinates
$x = r \setminus \cos \setminus \theta = 2 \setminus \cos \left(\frac{11 \setminus \pi}{6}\right) = 2 \setminus \cos \left(\setminus \frac{\pi}{6}\right) = 2 \setminus \cdot \setminus \frac{\sqrt{3}}{2} = \setminus \sqrt{3}$
$y = r \setminus \sin \setminus \theta = 2 \setminus \sin \left(\frac{11 \setminus \pi}{6}\right) = - 2 \setminus \sin \left(\setminus \frac{\pi}{6}\right) = - 2 \setminus \cdot \frac{1}{2} = - 1$
Now, take $x = \setminus \sqrt{3}$ units on +ve axis & $y = 1$ unit on -ve y-axis to specify the location of given point