Question

How do you plot the polar coordinate `(2, (11pi)/6)`?

Answer 1

The given polar coordinates `(r, \theta)\equiv (2, {11\pi}/6)` has the following Cartesian coordinates

`x=r\cos\theta=2\cos({11\pi}/6)=2\cos(\pi/6)=2\cdot\sqrt3/2=\sqrt3`

`y=r\sin\theta=2\sin({11\pi}/6)=-2\sin(\pi/6)=-2\cdot1/2=-1`

Now, take `x=\sqrt3` units on +ve axis & `y=1` unit on -ve y-axis to specify the location of given point