How do you rationalize the denominator and simplify #3/(sqrt5+sqrt6)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Dean R. Apr 18, 2018 We multiply by # \frac{ sqrt{5} - sqrt{6} }{ sqrt{5} - sqrt{6} } # to rationalize the denominator. Explanation: # frac {3} {sqrt{5} + sqrt{6} } # # = frac {3} {sqrt{5} + sqrt{6} } cdot \frac{ sqrt{5} - sqrt{6} }{ sqrt{5} - sqrt{6} } # # = frac { 3 sqrt{5} - 3 sqrt{6} } { 5 - 6 }# # = 3 sqrt{6} - 3 sqrt{5} # Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1802 views around the world You can reuse this answer Creative Commons License