How do you rationalize the denominator #sqrt(5/6)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer George C. May 31, 2015 Multiply both numerator and denominator by #sqrt(6)# : #sqrt(5/6) = sqrt(5)/sqrt(6) = sqrt(5)/sqrt(6)*sqrt(6)/sqrt(6)# #= (sqrt(5)sqrt(6))/((sqrt(6))^2) = (sqrt(5*6))/6# #=sqrt(30)/6# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 5590 views around the world You can reuse this answer Creative Commons License