Question

How do you rationalize the Lewis structures of the known compounds `XeF_2`, `XeF_4`, and `XeF_6`?

Answer 1

Well for `XeF_2` we gots `8+2xx7=22*"electrons...."`

Explanation:

And for the molecular and electronic geometries we invoke simple VESPER.

For `XeF_2` the electronic geometry is `"trigonal bipyramidal"`; the molecular geometry is `"LINEAR"`....

For `XeF_4`, we have `8+4xx7=36`, `"18 electron pairs"`. the electronic geometry is `"octahedral"`; the molecular geometry is `"SQUARE PLANAR"`....

For `XeF_6`, we got `8+6xx7=50, "25 electron pairs......"`; the central xenon is associated with 6 bonding, and 1 non-bonding pairs of electrons; a conformationally mobile, mono-capped octahedron structure is indicated with respect to the electronic distribution. See here for structure.