How do you reorder these numbers from least to greatest: #2/5, 0, -3/2, -9/8, 8/7#?

2 Answers
Feb 5, 2017

#-3/2," "-9/8," "0," "2/5," "8/7#

Explanation:

Another method of comparing these numbers is to convert them to fractions which have a common denominator. IN this way you will avoid working with recurring decimals.
Note that some of the fractions are negative.

The LCM is #280#

#2/5 = 112/280#

#0 =0/280#

#-3/2 =( -420)/280" "larr# the smallest

#-9/8 = (-315)/280#

#8/7 = 320/280" "larr# the greatest

Now you compare the numerators.

Remember to use the numbers in their original form.

May 11, 2017

The order from least to greatest is #{-3/2,-9/8,0,2/5,8/7}#

Explanation:

I am just adding another answer as first of all, I feel taking GCD and then comparing is a bit complicated and secondly what one does if some irrational numbers such as #sqrt3# or #pi# etc. are included.

Hence, in my view it is better to convert all given numbers to decimal numbers say up to #4# or #5# or more places of decimals for a better result.

Now #2/5=0.400000#

#0=0.000000#,

#-3/2=-1.500000#

#-9/8=-1.125000#

#8/7=1.142857#

Comparing them we find that the order from least to greatest is

#{-3/2,-9/8,0,2/5,8/7}#