How do you rewrite into vertex form #f(x)=4x^2-16x+5#?
Please see the explanation.
The vertex form for a parabola that opens or down is:
f(x) = a(x - h)^2 + k
Please observe that, in the given equation,
Factor 4 out of the first 3 terms and group them with ()s:
We can find the value of h by setting the middle term equal to -2hx:
We know that three terms inside the ()s is equal to