How do you rewrite the following quadratic equation in vertex form: #y=x^2-8x+13#?

1 Answer
salamat
Mar 20, 2017

minimum vertex with value#- 3# at #(4, -3)#

Explanation:

#y = x^2 - 8 x + 13#

Consider coefficient of #x#, divide by 2 and make a parentesis and ssquare them. since infront of parentesis is +ve value, then deduct the squared number in parentesis in the equation to balance it.
#y = (x - 4)^2 - (-4)^2 + 13#
#y = (x - 4)^2 - 16 + 13#
#y = (x - 4)^2 - 3#

since infront of #(x-4)^2# is +ve sign, it is a minimum vertex with value#- 3# at #(4, -3)#

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