Step 1) Subtract #color(red)(60)# from each side of the equation to isolate the #n# term while keeping the equation balanced:
#A - color(red)(60) = 60 + (11n)/100 - color(red)(60)#
#A - 60 = 60 - color(red)(60) + (11n)/100#
#A - 60 = 0 + (11n)/100#
#A - 60 = (11n)/100#
Step 2) Multiply each side of the equation by #color(red)(100)/color(blue)(11)# to solve for #n# while keeping the equation balanced:
#color(red)(100)/color(blue)(11)(A - 60) = color(red)(100)/color(blue)(11) xx (11n)/100#
#(color(red)(100)(A - 60))/color(blue)(11) = cancel(color(red)(100))/cancel(color(blue)(11)) xx (color(blue)(cancel(color(black)(11)))n)/color(red)(cancel(color(black)(100))#
#(100(A - 60))/11 = n#
#n = (100(A - 60))/11#
Or
#n = (100A - 6000)/11#