How do you rewrite #x(x+2)+3(x+2)# as an equivalent product of two binomials?

Question

12196 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-30T19:08:11

#(x+2)(x+3)#

An expression such as #5x +15# can be factored by taking out the common factor of #5#.

#color(blue)(5)x+ color(blue)(5) xx 3#

#=color(blue)(5)(x+3)#

In the same way the expression can be factored by taking out the common bracket #(x+2)#

#x(color(blue)(x+2)) +3(color(blue)(x+2))#

#=color(blue)((x+2))(x+3)#

Answer 2 · 2017-05-30T19:14:24

#color(blue)((x+2)(x+3)#

#x(x+2)+3(x+2)#

#:.=x^2+2x+3x+6#

#:.=x^2+5x+6#

#:.color(blue)(=(x+2)(x+3)#