Question

How do you rewrite `y=-2x^2+35` in vertex form?

Answer 1

For this function it is both standard and vertex form. See explanation.

Explanation:

If you have a quadratic function in standard form, to find the vertex you can use those formulas:

`p=(-b)/(2a)`

and

`q=(-Delta)/(4a)`

Instead of using the formula for `q` you can substitute the value of `p` to the function formula.

If you calculate the vertex coordinates then the vertex form is:

`y=a(x-p)^2+q`

Here using the formulas we get:

`p=0`

If we calculate `q=f(0)=35` then the vertex form is:

`y=-2(x-0)^2+35`

After simplifying we get `y=-2x^2+35`, so the vertex form is identical with standard form for this function.