How do you rewrite #y = 3x^2 - 24x + 10# in vertex form?

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Answer 1 · 2017-07-15T13:43:03

The vertex form is #y=3(x-4)^2-38#

The vertex form of a parabola is

#y=a(x-h)^2+k#

Here, we have

#y=3x^2-24x+10#

#y=3(x^2-8x)+10#

We complete the square by adding half of the coefficient of #x# squared and substract this value.

#y=3(x^2-8x+16-16)+10#

#y=3(x^2-8x+16)+10-48#

#y=3(x-4)^2-38#

The vertex is #=(h,k)=(4,-38)#

graph{3(x-4)^2-38 [-42.64, 39.6, -46.42, -5.33]}