# How do you rewrite #y = x^2 + 14x + 29# in vertex form?

##### 2 Answers

Nov 26, 2017

#y=(x+7)^2+20#

#### Explanation:

Given -

#y=x^2+14x+29#

Vertex form of the equation is -

#y=a(x-h)^2-k#

Where -

#a -# is the coefficient of#x^2#

#h-# is the x-coordinate of the vertex

#k-# is the y-coordinate of the vertex

First, find the vertex of the given equation

#x=(-b)/(2a)=(-14)/2=-7#

#y=(-7)^2+14(-7)+29=49-98+29=-20#

Vertex

#a=1#

Substitute these values in the formula

#y=(x-(-7))^2-(-20)#

#y=(x+7)^2+20#

Nov 26, 2017

#### Explanation:

Vertex form is

Use the process of **completing the square**

This is vertex form.

The vertex will be at