# How do you show the reaction of sulfurous acid with lithium hydroxide to form water and lithium sulfite?

${H}_{2} S {O}_{3} \left(a q\right) + 2 L i O H \left(a q\right) \rightarrow L {i}_{2} S {O}_{3} \left(a q\right) + 2 {H}_{2} O \left(l\right)$
In aqueous solution, we know that so-called $\text{sulfurous acid}$ is probably solvated $S {O}_{2} \left(a q\right)$, i.e. $S {O}_{2} \cdot {H}_{2} O \equiv {H}_{2} S {O}_{3}$.