How do you simplify #1/2 + 2/3 + 3/4 #? Prealgebra Fractions Equivalent Fractions and Simplifying 1 Answer Shwetank Mauria · Tony B Aug 2, 2016 #1/2+2/3+3/4=23/12=1 11/12# Explanation: To simplify #1/2+2/3+3/4#, we can add them if the denominators are common. Now as LCD of the denominators #2#, #3# and #4# is #12# #1/2+2/3+3/4# #=(1/2xx1)+(2/3xx1)+(3/4xx1)# = #(1xx6)/(2xx6)+(2xx4)/(3xx4)+(3xx3)/(4xx3)# = #6/12+8/12+9/12# = #(6+8+9)/12# = #23/12# or #((12+11)/12)# or #(12/12+11/12)# or #1 11/12# Answer link Related questions What is 0.098 divided by 7? How do you find the fraction notation and simplify 16.6%? How do you convert #0.bar(45)# (meaning the #45# is being repeated) to a fraction? How do you convert 0.40 (40 repeating) to a fraction? How do you convert 8/15 to a decimal? How do you express #3/4, 7/16,# and #5/8# with the #LCD#? How do you simplify fractions? What is the simplified form of #30/42#? How do you subtract and simplify #9-5 1/3#? How do you add and simplify #5/7 + 3/4#? See all questions in Equivalent Fractions and Simplifying Impact of this question 37676 views around the world You can reuse this answer Creative Commons License