How do you simplify #(-1)(-2+3)-(4-9)(-2)#?

2 Answers
Nov 12, 2015

Answer:

#-11#.

Explanation:

We use BIDMAS/PEDMAS for this operation. So,
we start with the brackets, adding all values inside a specific bracket:
#(-2+3) = (1)#,
#(4-9) = (-5)#.

We have added all values within brackets. Now we have:
#(-1)(1)-(-5)(-2)#. We have no exponentials/indices nor divisions, so we move on to multiplications:
#(-1)(1) = (-1)#,
#(-5)(-2) = (10)#.

We have multiplied. Now we've got:
#(-1) - (10) = -11#.

Hope it Helps! :D .

Aug 1, 2016

Answer:

#-11#

Explanation:

Count the number of terms first. There are only 2, but there are parentheses in each term which need to be worked out first.

#color(red)((-1)(-2+3)) color(blue)(- (4-9)(-2))#
=#color(red)((-1) xx (1)) - color(blue)((-5)(-2))#

=#color(red)-1 - color(blue)(10)#

=#-11#