# How do you simplify 1/(2i)^3?

$\frac{1}{2 i} ^ 3 = - \frac{1}{8 i}$
$\frac{1}{2 i} ^ 3 = \frac{1}{{2}^{3} {i}^{3}} = \frac{1}{8} \times \frac{1}{i} ^ 3 = \frac{1}{8} \times \frac{1}{i} ^ 2 \times \frac{1}{i} = \frac{1}{8} \times \left(\frac{1}{-} 1\right) \times \frac{1}{i}$
$= - \frac{1}{8 i}$