How do you simplify #(-2^3-8*2^2)/(80-:4^2-(4-|4-13|)#?

2 Answers
Jul 26, 2016

Use the PEMDAS method to simplify the fraction and get the answer.

Explanation:

PEMDAS stands for Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction. There is a set of parentheses in the denominator, so let's solve for that:

#(4-|4-13|)=(4-9)=-5#

We now have #(-2^3-8*2^2)/(80//4^2+5)#.

Next is Exponents. We have a few of those:
#-2^3=-2*-2*-2=-8#
#2^2=2*2=4#
#4^2=4*4=16#

We now have #(-8-8*4)/(80//16+5)#.

Next is Multiplication. We have multiplication in the numerator: #8*4=32#. We now have #(-8-32)/(80//16+5)#.

Next is Division. We have division in the denominator: #80/16=5#. We now have #(-8-32)/(5+5)#.

From here, it's easy. Just add 5 and 5 to get 10 and subtract 32 from -8 to get -40. We now have #(-40)/(10)#. From here, just divide -40 by 10 to get our answer, #-4#.

Jul 30, 2016

=#-4#

Explanation:

Rather than blindly following PEDMAS, BODMAS, PEMDSA or any other variations, which often lead to incorrect answers, you will do better by knowing that the various operations are not equally powerful.

The strongest operations are the powers and roots and are therefore done FIRST.

Multiplication and division are done next and LAST are the additions and subtractions. ("OF" is a strong multiply)

If a weaker operation must be done first, parentheses are used to indicate this.

So, always identify and count the individual TERMS first.
Each term will lead to an answer and these answers are added or subtracted in the LAST step.

#(-2^3-8*2^2)/(80div4^2 - (4 - |4-13|))" is all one term"#

But there are 2 terms in the numerator and 2 in the denominator.
Evaluate each term separately, but they can be done at the same time.The entire expression is carried down from one line to next, but something is done to each term in each line.

=#(color(red)(-2^3)color(green)(-8*2^2))/(color(blue)(80div4^2)color(magenta)( - (4-|4-13|)))" "|4-13| = 9 #

=#(color(red)(-8)color(green)(-8xx4))/(color(blue)(80div16)color(magenta)( -(4- 9))#

=#(color(red)(-8)color(green)(-32))/(color(blue)(5)color(magenta)( -(-5))#

=#(-40)/(5+5) = (-40)/(10)#

=#-4#

Ironically, the final operation in this case is 'division'.