How do you simplify #2/(3-sqrt(3x^2))#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Binayaka C. Jan 28, 2018 # (2(3+sqrt3 *x)) /(3(3- x^2)) # Explanation: #2/(3-sqrt(3x^2))= 2/(3-sqrt3 *x) # . Multiplying both numerator and denominator by #(3+sqrt3 *x) # we get , #(2(3+sqrt3 *x)) /((3-sqrt3 *x)(3+sqrt3 *x)) # #=(2(3+sqrt3 *x)) /(3^2- (sqrt3 *x)^2) # # =(2(3+sqrt3 *x)) /(9- 3 *x^2) # # =(2(3+sqrt3 *x)) /(3(3- x^2)) # [Ans] Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1367 views around the world You can reuse this answer Creative Commons License