# How do you simplify (2-3i)/(1-2i)?

$\frac{8 + i}{5}$
Multiply both the numerator and the denominator by the conjugate of the denominator $1 - 2 i$, which is $1 + 2 i$: (since the conjugate of a complex number $a + b i$ equals to $a - b i$)
((2-3i)(1+2i))/((1-2i)(1+2i)= $\frac{2 + 4 i - 3 i - 6 {i}^{2}}{{1}^{2} - {\left(2 i\right)}^{2}}$ = $\frac{2 + i + 6}{1 - \left(- 4\right)}$ $= \frac{8 + i}{5}$