# How do you simplify  (2 + i)(2+3i)?

Follow the normal multiplication rules, and remember that ${i}^{2} = - 1$
$= 2 \cdot 2 + 2 \cdot 3 i + i \cdot 2 + i \cdot 3 i$
$= 4 + 6 i + 2 i + 3 {i}^{2}$
$= 4 + 8 i + 3 \cdot \left(- 1\right)$
$= 1 + 8 i$