# How do you simplify 2 root3( 128)?

Jul 22, 2016

$8 \sqrt[3]{2}$

#### Explanation:

Write 128 as the product of its prime factors, so we know what we are working with.

$128 = {2}^{7}$

$2 \sqrt[3]{{2}^{6} \times 2} \text{ group indices in threes}$

=$2 \times {2}^{2} \sqrt[3]{2}$

=$8 \sqrt[3]{2}$