How do you simplify #2\sqrt { 20v ^ { 7} }#?

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Answer 1 · 2017-10-16T11:55:58

See a solution process below:

We can rewrite this expression as:

#2sqrt(4v^6 * 5v)#

Now, use this rule for radicals to complete the simplification:

#sqrt(color(red)(a) * color(blue)(b)) = sqrt(color(red)(a)) * sqrt(color(blue)(b))#

#2sqrt(color(red)(4v^6) * color(blue)(5v)) => 2sqrt(color(red)(4v^6)) * sqrt(color(blue)(5v)) => (2 * 2v^3)sqrt(5v) => 4v^3sqrt(5v)#

Answer 2 · 2017-10-16T12:03:15

#=4v^3sqrt5v#

#2sqrt(20v^7)#

#:.=2sqrt(2*2*5*v*v*v*v*v*v*v#

#:.sqrtaxxsqrta=a#

#:.=2*2*v^3sqrt(5v)#

#:.=4v^3sqrt(5v)#