# How do you simplify 2 sqrt(3) times 4 sqrt(2)?

$8 \sqrt{6}$
You treat the square root and the natural number differently. First you multiply the $2$ and $4$, and then you do the math inside the square root which would be $3$ and $2$. Then you put them together, and you get the answer.
$2 \sqrt{3} \cdot 4 \sqrt{2} = 2 \cdot 4 \cdot \sqrt{3 \cdot 2} = 8 \sqrt{6}$