# How do you simplify (-2i)(-6i)(4i)?

Jan 12, 2017

$- 48 i$

#### Explanation:

$\textcolor{\mathmr{and} a n \ge}{\text{Reminder }} \textcolor{red}{\overline{\underline{| \textcolor{w h i t e}{\frac{2}{2}} \textcolor{b l a c k}{{i}^{2} = {\left(\sqrt{- 1}\right)}^{2} = - 1} \textcolor{w h i t e}{\frac{2}{2}} |}}}$

We can find the product of the first pair.

$\text{That is } \left(- 2 i\right) \left(- 6 i\right) = 12 {i}^{2} = - 12$

$\text{Then } - 12 \left(4 i\right) = - 48 i$