How do you simplify (2k)/8 + (3k)/6?

Jun 4, 2016

Start simplifying the number in front of $k$ with the denominator

$\frac{2 k}{8} = \frac{2 k}{2 \cdot 4} = \frac{k}{4}$

$\frac{3 k}{6} = \frac{3 k}{2 \cdot 3} = \frac{k}{2}$

Now we have

$\frac{2 k}{8} + \frac{3 k}{6} = \frac{k}{4} + \frac{k}{2}$

We use as common denominator $4$.

$\frac{k}{4} + \frac{k}{2} = \frac{k}{4} + \frac{2 k}{4}$

$= \frac{k + 2 k}{4}$

$= \frac{3 k}{4}$.

You cannot simplify more because 3 and 4 do not share any factor.