How do you simplify #(2sin^2x)/cos^3x*(cosx/(2sinx))^2#?
1 Answer
Apr 10, 2018
Expand and cancel.
#=(2sin^2x)/cos^3x * cos^2x/(4sin^2x)#
#=1/(2cosx)#
#=1/2secx#
Hopefully this helps!
