How do you simplify #2sqrt(28)#?

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Answer 1 · 2015-09-26T09:09:19

#2 sqrt(28) = 4 sqrt(7)#

When #a >= 0#, #sqrt(a^2) = a#

and when #a, b >= 0#, #sqrt(ab) = sqrt(a)sqrt(b)#

So:

#2 sqrt(28) = 2 sqrt(2*2*7) = 2 sqrt(2*2) sqrt(7) = 2*2 sqrt(7) = 4 sqrt(7)#

Answer 2 · 2015-09-26T09:09:34

#2sqrt(28)=4sqrt(7)#

#2*sqrt(28)=2*sqrt(4*7)=2*sqrt(4)*sqrt(7)=4sqrt(7)#