# How do you simplify (2sqrt4)/(8sqrt3)?

Sep 4, 2016

$\frac{\sqrt{3}}{6}$

#### Explanation:

$\frac{2 \sqrt{4}}{8 \sqrt{3}} = \frac{2 \times 2}{8 \sqrt{3}} = \frac{1}{2 \sqrt{3}}$

$\frac{1}{2 \sqrt{3}} \times \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3}}{2 \times 3} = \frac{\sqrt{3}}{6}$

Sep 4, 2016

$\frac{\sqrt{3}}{6}$

#### Explanation:

We have: $\frac{2 \sqrt{4}}{8 \sqrt{3}}$

$= \frac{2 \cdot 2}{8 \sqrt{3}}$

$= \frac{4}{8 \sqrt{3}}$

$= \frac{1}{2 \sqrt{3}}$

Now, let's rationalise the denominator by multiplying both the numerator and denominator by $\sqrt{3}$:

$= \frac{1}{2 \sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}$

$= \frac{\sqrt{3}}{2 \cdot 3}$

$= \frac{\sqrt{3}}{6}$