How do you simplify #(2t-2)/(1-t)#?

1 Answer
Shwetank Mauria
Aug 2, 2016

#(2t-2)/(1-t)=-2#

Explanation:

Observe that when we take #2# common from numerator, we are left with #t-1#, which is exactly negative of denominator i.e. denominator is #(-1)(t-1)#. Hence using this

#(2t-2)/(1-t)#

= #(2(t-1))/((-1)(1-t))#

= #(2cancel((t-1)))/((-1)cancel((1-t)))#

= #2/-1=-2#

Related questions
See all questions in Division of Polynomials
Impact of this question
1561 views around the world
You can reuse this answer
Creative Commons License