How do you simplify (2tan(x+1))/(1-tan^2(x+1))?

$\frac{2 \tan \left(x + 1\right)}{1 - {\tan}^{2} \left(x + 1\right)} = \tan 2 \left(x + 1\right)$
$\tan 2 A = \frac{2 \tan A}{1 - {\tan}^{2} A}$
$\frac{2 \tan \left(x + 1\right)}{1 - {\tan}^{2} \left(x + 1\right)} = \tan 2 \left(x + 1\right)$