How do you simplify #(2x^6y^2)(-2x^5y^-1)#?
1 Answer
Mar 1, 2016
Explanation:
Group like terms with one another.
#=(2xx-2)(x^6xxx^5)(y^2xxy^-1)#
To deal with the variable terms, use the rule about multiplying exponential terms with the same base:
#a^bxxa^c=a^(b+c)#
This gives us
#=-4x^(6+5)y^(2-1)#
#=-4x^11y^1#
#=-4x^11y#
