# How do you simplify (2y^2-4y)/(16y)?

Jun 1, 2017

$\frac{y - 2}{8}$; $y \ne 0$

#### Explanation:

We have: $\frac{2 {y}^{2} - 4 y}{16 y}$

Let's factorise the numerator:

$= \frac{2 y \left(y - 2\right)}{16 y}$

Simplifying:

$= \frac{y - 2}{8}$

In the original fraction, the denominator is $16 y$.

To prevent division by zero, this denominator cannot be equal to zero:

$R i g h t a r r o w 16 y \ne 0$

$R i g h t a r r o w y \ne 0$

$\therefore \frac{y - 2}{8}$; $y \ne 0$