How do you simplify (3+9i)/(3i)? Precalculus Complex Numbers in Trigonometric Form Division of Complex Numbers 1 Answer Ratnaker Mehta Sep 5, 2016 (3+9i)/(3i)=(cancel(3)(1+3i))/((cancel3)i)=(1+3i)/i=(1+3i)/i xxi/i=(i+3i^2)/i^2=(i-3)/-1=3-i. Explanation: Alternatively, (3+9i)/(3i)=3/(3i)+(9i)/(3i)=1/i+3={(1*i)/(i*i)}+3 =i/i^2+3=i/-1+3=3-i. Answer link Related questions How do I graphically divide complex numbers? How do I divide complex numbers in standard form? How do I find the quotient of two complex numbers in polar form? How do I find the quotient (-5+i)/(-7+i)? How do I find the quotient of two complex numbers in standard form? What is the complex conjugate of a complex number? How do I find the complex conjugate of 12/(5i)? How do I rationalize the denominator of a complex quotient? How do I divide 6(cos^circ 60+i\ sin60^circ) by 3(cos^circ 90+i\ sin90^circ)? How do you write (-2i) / (4-2i) in the "a+bi" form? See all questions in Division of Complex Numbers Impact of this question 2556 views around the world You can reuse this answer Creative Commons License