How do you simplify 3 times (-2) +6 -(-2) - 5 using order of operations?

Apr 20, 2018

$- 2$

Explanation:

So following orders of operations:

$1. B$ =Brackets
$2. E$ = Exponents
$3. M$ = Multiplication
$4. D$ = Divison
$5. A$ = Addition
$6. S$ = Subtraction

$3 \cdot \left(- 2\right) + 6 - \left(- 2\right)$

Following orders of operation we start with the brackets. So we get:

$\textcolor{red}{3 \cdot - 2} + 6 \textcolor{red}{- -} 2 \Leftarrow$ remeber that:$- - = +$

Because there's no exponents and we already multiplied in the first step, there's no multiplication we need to do, same with the division, there's no division we need to do.

So now we have:

$- 6 + 6 + 2$

And what we need to do now is add and subtract ( you can do subraction or addition in any order, same with multiplication and divison).

$- 6 + 6 + 2 = 2$

The two sixes take out eachother so we just have 2.

Hope this helps!