How do you simplify #3times(11!)/(7!4!)#?

1 Answer
EZ as pi · maganbhai P.
Jul 19, 2016

#990#

Explanation:

#(3xx11*10*9*8*7!) / (7!*4*3*2*1 )=(cancel3xx11*10*9*8*cancel(7!)) / (cancel(7!)*4*cancel3*2*1 )#

= #(11*10*9*cancel8 )/(cancel(4*2))#

=#11*10*9#

=# 990#

Related questions
See all questions in Factorial Identities
Impact of this question
1612 views around the world
You can reuse this answer
Creative Commons License