# How do you simplify (3w^2-12)/(w^2+5w+6)?

Sep 20, 2016

We must factor both the numerator and the denominator.

$= \frac{3 \left({w}^{2} - 4\right)}{\left(w + 3\right) \left(w + 2\right)}$

$= \frac{3 \left(w + 2\right) \left(w - 2\right)}{\left(w + 3\right) \left(w + 2\right)}$

$= \frac{3 \left(w - 2\right)}{w + 3}$

Finally, let's note the restrictions on the variable. We cannot have the denominator equal 0, so $w \ne 3 \mathmr{and} - 2$.

Hopefully this helps!