How do you simplify #3x^(2/3) y^(3/4) (2x^(5/3) y^(1/2))^3 #? Prealgebra Exponents, Radicals and Scientific Notation Exponents 1 Answer Shwetank Mauria Jun 1, 2016 #3x^(2/3)y^(3/4)(2x^(5/3)y^(1/2))^3=24x^(13/3)y^(9/4)# Explanation: #3x^(2/3)y^(3/4)(2x^(5/3)y^(1/2))^3# = #3x^(2/3)y^(3/4)(2^3(x^(5/3))^3(y^(1/2))^3)# = #3x^(2/3)y^(3/4)*8(x^(5/3xx3))(y^(1/2xx3))# = #24x^(2/3)y^(3/4)(x^5)(y^(3/2))# = #24x^(2/3+5)y^(3/4+3/2)# = #24x^(13/3)y^(9/4)# Answer link Related questions How do you simplify #c^3v^9c^-1c^0#? How do you simplify #(- 1/5)^-2 + (-2)^-2#? How do you simplify #(4^6)^2 #? How do you simplify #4^3ยท4^5#? How do you simplify #(5^-2)^-3#? How do you simplify and write #(-5.3)^0# with positive exponents? How do you factor #12j^2k - 36j^6k^6 + 12j^2#? How do you simplify the expression #2^5/(2^3 times 2^8)#? When can I add exponents? What is the Zero Exponent Rule? See all questions in Exponents Impact of this question 3385 views around the world You can reuse this answer Creative Commons License