How do you simplify #(3x-6)/(x-2)#?

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Answer 1 · 2018-03-26T08:41:13

Follow explanation. Your answer is 3.

Try to write down #3x-6# in a new form:

#[3(x-2)]/(x-2)#

#=3#

This is your answer #3#.

Answer 2 · 2018-03-26T08:44:59

#3#

#"factorise the numerator"#

#rArr(3x-6)/(x-2)#

#=(3cancel((x-2)))/cancel((x-2))^1=3#