# How do you simplify (4-2(x-1))/(x^2-6x+9)?

Nov 26, 2015

$\frac{- 2}{x - 3}$

#### Explanation:

$\frac{4 - 2 \left(x - 1\right)}{{x}^{2} - 6 x + 9}$

$= \frac{4 - 2 x + 2}{{x}^{2} - 6 x + 9}$

=(-2x+6)/(x^2-6x+9

$= \frac{- 2 \left(x - 3\right)}{\left(x - 3\right) \left(x - 3\right)}$

$= \frac{- 2 \textcolor{red}{\cancel{\textcolor{b l a c k}{\left(x - 3\right)}}}}{\textcolor{red}{\cancel{\textcolor{b l a c k}{\left(x - 3\right)}}} \left(x - 3\right)}$

$= \frac{- 2}{x - 3}$

Note:
$\frac{4 - 2 \left(x - 1\right)}{{x}^{2} - 6 x + 9}$ is not the same as $\frac{\left(4 - 2\right) \left(x - 1\right)}{{x}^{2} - 6 x + 9}$